﻿ a sample of saturated sand has a dry unit weight of 18 kn

a sample of saturated sand has a dry unit weight of 18 kn

specializing in the production of large, medium and small concrete mixers, concrete mixing stations, stabilized soil mixing stations and other equipment. It is a heavy industry enterprise integrating R & production and sales. A sample of saturated sand has a dry unit weight of 18 kN ...

Oct 29, 2015  A sample of saturated sand has a dry unit weight of 18 kN/m 3 and a specific gravity of 2.7. If water is 10 kN/m 3, the void ratio of the soil sample will be. 0.5.

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Q.39. A saturated sand sample has a dry unit weight of 18 kN/m3 and a specific gravity of 2.65. If w = 10 kN/m3, the water content of the soil is (a) 0.10 (b) 0.178 (c) 0.187 (d) none of these Q.40. The saturated and dry densities of a soil are respectively 2000 kg/m3 and 1500 kg/m3. The water content(in percentage) of the soil in the

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Apr 10, 2021  Civil Engineering questions and answers. A soil sample has a dry unit weight of 18.4 KN/mº, moisture content of 12% and a specific gravity of solids particles is 2.6. What is the saturated unit weight? 19.35 kN/m O 21 13 kN/m O 22.57 kN/m 24.08 kN/m.

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Question: A Saturated Soil Sample Has A Total Unit Weight Of 18.24 KN/m^3 With Specific Gravity Of Solids As 2.72. Calculate The Following: A. The Dry Unit Weight B. The Void Ratio C. Porosity D. Total Unit Weight At 80% Saturation.

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Nov 22, 2016  Solution: Since you know the volume and the dry weight, you can calculate the dry unit weight and then find e. The porosity can be found using the void ratio porosity relationship. Calculate the weight of dry sand. Weight of sand and container = 52.3 N Weight of container = 9.8 N Weight of dry sand, W s = 52.3 – 9.8 = 42.5 N = 0.0425 kN

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A saturated sand sample has a dry unit weight of 18 kN/m' and a specific gravity of 2.65. If yw = 10 kN/m”, the water content of the soil is ; Question: A saturated sand sample has a dry unit weight of 18 kN/m' and a specific gravity of 2.65. If yw = 10 kN/m”, the water content of the soil is

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Oct 29, 2015  A sample of saturated sand has a dry unit weight of 18 kN/m 3 and a specific gravity of 2.7. If water is 10 kN/m 3, the void ratio of the soil sample will be. 0.5.

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Q.39. A saturated sand sample has a dry unit weight of 18 kN/m3 and a specific gravity of 2.65. If w = 10 kN/m3, the water content of the soil is (a) 0.10 (b) 0.178 (c) 0.187 (d) none of these Q.40. The saturated and dry densities of a soil are respectively 2000 kg/m3 and 1500 kg/m3. The water content(in percentage) of the soil in the

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A saturated sand sample has a dry unit weight of 18 kN/m 3 and a specific gravity of 2.65. If γ w = 9.81 kN/m 3 , then, what is the water content of the soil? 0.166

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Feb 08, 2021  The Questions and Answers of A sample of saturated soil has a water content of 25 percent and bulk unit weight of 20 KN/m^3 determine the dry unit weight ,void ratio and specific gravity of solids? are solved by group of students and teacher of Civil Engineering (CE), which is also the largest student community of Civil Engineering (CE).

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Unit Weights of Soil. Symbols and Notations γ, γ m = unit weight, bulk unit weight, moist unit weight γ d = Dry unit weight γ sat = Saturated unit weight γ b, γ ' = Buoyant unit weight or effective unit weight γ s = Unit weight of solids γ w = Unit weight of water (equal to 9810 N/m 3) W = Total weight of soil W s = Weight of solid particles W w = Weight of water V = Volume of soil

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A soil sample has avoid ratio of 0.72, moisture content = 12% and GS determine the following: a) Dry unit weight, moist unit weight (KN/m3). b) Weight of water in KN/m3 to be added for 80% degree of saturation. c) Is it possible to reach a water content of 30% without change the present void ratio.

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2 Problem2 The unit weight of a soil sample is 18.2 kN/m3 at water content of 30.55 %. The degree of saturation is increased from 30% to 80% when the water content is increased by16%. Required: 1) The degree of saturation of the soil sample 2) The specific gravity and void ratio 3) The air content of the soil sample.

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Solution: Since you know the volume and the dry weight, you can calculate the dry unit weight and then find e. The porosity can be found using the void ratio porosity relationship. Calculate the weight of dry sand. Weight of sand and container = 52.3 N Weight of container = 9.8 N Weight of dry sand, W s = 52.3 – 9.8 = 42.5 N = 0.0425 kN

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A saturated sand sample has a dry unit weight of 20 kN/m° and a specific gravity of 2.65. If yw = 10 kN/m3, the water content of the soil is O 17.82 % 13.26% O 15.36 % 12.26%

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= in situ dry unit weight (at a void ratio of e) = dry unit weight in the densest condition (at a void ratio of emin) In the natural state, a moist soil has a volume of 0.0093 rn3 and weighs 177.6 N. The oven dry weight of the soil is 153.6 N. If GS = 2.71, calculate the moisture content, moist unit weight, dry unit weight, void ratio, porosity ...

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A saturated undisturbed sample from a clay strata has moisture content of 22.22% and specific weight of 2.7. Assuming γ w = 10 kN/m 3 , the void ratio and the saturated unit weight of

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Example 2.2 If a soil has a void ratio of 0.7 and a specific gravity of 2.72, calculate the following: (a) Dry unit weight (b) Saturated unit weight (c) Submerged unit weight Also compute the unit weight and water content at a degree of saturation of 75%.

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A saturated sand sample has a dry unit weight of 18 kN/m 3 and a specific gravity of 2.65. If γ w = 9.81 kN/m 3 , then, what is the water content of the soil? 0.166

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A saturated sand sample has a dry unit weight of 18 kN/m3 and a specific gravity of 2.65. If γw = 9.81 kN/m3, then, what is the water content of the soil? Q32.

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Saturated unit weight ... 9.81 = 6.7 KN/m 3 Example The porosity of a sand sample is 0.4. Assuming a specific gravity of 2.68, compute void ratio, ... require a water content of 18% and dry unit weight of 1.76 g/cc. Calculate the quantity of soil required to be excavated for the embankment.

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Sep 27, 2020  The image above represents dry unit weight of soil. To compute for dry unit weight of soil, two essential parameters are needed and these parameters are Unit weight of soil (γ) and Moisture content (w). The formula for calculating dry unit weight of soil: γ d = γ / 1 + w. Where: γ d = Dry Unit Weight of Soil γ = Unit Weight of Soil

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Laboratory test data on a sample of saturated soil show that the void ratio is 0.45 and the specific gravity of solids is 2.65. For these conditions, determine the following: a.) water content b.) saturated unit weight c.) dry unit weight. 55.) A soil sample has a bulk unit weight

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Determine the void ratio of a saturated soil sample that has a mass of 178 g before drying and 139 g after drying in an oven. Assume the specific gravity of the soil solids to be 2.7. For a saturated soil S r = 1 Void ratio, e = m × G s = 0.28 × 2.7 = 0.756

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= 10.69 kN/m ] 6] A partially saturated soil from an earth fill has a natural water content of 19% and bulk unit Weight of 19.33 kN/m 3. Assuming the specific gravity of soil solid as 2.6, compute the degree of saturation and void ratio if subsequently the soil gets saturated, determine the dry unit weight and saturated unit weight.

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A soil sample has a mass of 3kg and volume of 0.0016 m 3 in natural condition. After being oven dried in an oven, the mass of the sample is 2.6kg. Specific gravity (G) is 2.7. Unit weight of water is 10 kN/m 3. The air content of the soil is:

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Mar 29, 2015  If so, which one of these values is wrong, and what should be its correct value? 3 3 18.4 26.1 40% 1.12 95% S kN Given unit weight of sample m kN unit weight of solids m w water content e voids ratio S degree of saturation γ γ = = = = = = = = = = Solution: ( )( ) ( ) ( ) 3 Check the accuracy of 4 out of 5 of the variables using, 0.95 1.12 1 ...

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Feb 13, 2020  Saturated unit weight. When the soil mass is saturated, its bulk unit weight is called the saturated unit weight. Thus, saturated unit weight is the ratio of the total weight of a saturated soil sample to its total volume. (v) Submerged unit weight.

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Example 2.2 If a soil has a void ratio of 0.7 and a specific gravity of 2.72, calculate the following: (a) Dry unit weight (b) Saturated unit weight (c) Submerged unit weight Also compute the unit weight and water content at a degree of saturation of 75%.

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stress at the sand surface in the dense, saturated state. Take the unit weight of water as 9.81kN/m3. Q1.5 Solution (a) In the loose dry state, the vertical total stress is given by the unit weight of the sand × the depth h. The depth of the sand is given by the volume, 1200cm3, divided by the cross-

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Specific Weight or Unit weight of Sand. Unit weight or Specific Weight of sand is calculated by the product of the density of sand and the standard gravity of sand. According to the US customary measurement system, dry weighs 1.631 gram per cubic centimeter, this density is equal to 101.8 pounds per cubic foot [lb/ft³].

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= in situ dry unit weight (at a void ratio of e) = dry unit weight in the densest condition (at a void ratio of emin) In the natural state, a moist soil has a volume of 0.0093 rn3 and weighs 177.6 N. The oven dry weight of the soil is 153.6 N. If GS = 2.71, calculate the moisture content, moist unit weight, dry unit weight, void ratio, porosity ...

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